Question

For a d – electron the orbital angular momentum is

• A. $\sqrt{6}\frac{h}{2\pi }$
• B. $\frac{\sqrt{2}h}{2\pi }$
• C. $\frac{h}{2\pi }$
• D. $\frac{2h}{\pi }$

Answer 1

The correct option is A $\sqrt{6}\frac{h}{2\pi }$

Orbital angular momentum $=\sqrt{l(l+1)}\frac{h}{2\pi }$
For a d - orbital l = 2
Orbital angular momentum $=\sqrt{2(2+1)}\frac{h}{2\pi }$
$=\frac{\sqrt{6}h}{2\pi }$