Question

For a '$d$' electron, the orbital angular momentum is

• A. $\sqrt{6}\left(\frac{h}{2\pi }\right)$
• B. $\sqrt{2}\left(\frac{h}{2\pi }\right)$
• C. $\left(\frac{h}{2\pi }\right)$
• D. $2\left(\frac{h}{2\pi }\right)$

Answer 1

The correct option is A $\sqrt{6}\left(\frac{h}{2\pi }\right)$

The expression for orbital angular momentum is
$=\sqrt{l(l+1)}\left(\frac{h}{2\pi }\right)$
For $d-$ orbital, $l=2$
Hence, $L=\sqrt{2(2+1)}\left(\frac{h}{2\pi }\right)=\sqrt{6}\left(\frac{h}{2\pi }\right)$