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Reaction with Metals

For a dibasic...

Question

For a dibasic acid, normality is twice the molarity for a given solution.

A

True

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B

False

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Solution

The correct option is A True
$N o r m a l i t y = M o l a r i t y \times n_{f a c t o r}$
For dibasic acid,
$n_{f a c t o r} = b a s i c i t y = 2$
$N o r m a l i t y = M o l a r i t y \times 2$

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