Question

For a electrolytic conductor, the transport number of cation is given by
$t_{+}\text{is the transport number of cation}$
$t_{-}\text{is the transport number of anion}$

• A. $t_{+}=\frac{\text{Current carried by the cations}}{\text{Total current carried by both the ions}}$
• B. $t_{+}=\frac{\text{Current carried by the cation}}{\text{Current carried by the anion}}$
• C. $t_{+}=\frac{\text{Total current carried by both the ions}}{\text{Current carried by the cations}}$
• D. $t_{+}=\frac{\text{Current carried by the anions}}{\text{Current carried by the cation}}$

Answer 1

The correct option is A $t_{+}=\frac{\text{Current carried by the cations}}{\text{Total current carried by both the ions}}$

Transport number:
For electrolytic conductors, the current is carried by both cations and anions.Transport number of any ion is the fraction of total current (by all the ions) carried by that ion.
$t_{+}=\frac{\text{Current carried by the cations}}{\text{Total current carried by both the ions}}$

$t_{-}=\frac{\text{Current carried by the anions}}{\text{Total current carried by both the ions}}$

Adding both equations:
$t_{+}+t_{-}=1$