Question

For a first order reaction rate constant is given as $\log K=14-\frac{1.2\times {10}^4}{T}$ then what will be value of temperature if its half life period is $6.93\times {10}^{-3}min$?

• A. $100K$
• B. $1000K$
• C. $720K$
• D. $327K$

Answer 1

The correct option is B $1000K$

$k=\frac{0.693}{t_{1/2}}$

$k=100{min}^{-1}$

Substituting it, we get

$2=14-\frac{1.2\times {10}^4}{T}$

$t=1000K$