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Half life

For a first o...

Question

For a first order reaction, $t_{7 / 8} = n \times t_{1 / 2}$
The value of $n$ will be:

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Solution

For $t_{7 / 8}$ , $a_{t} = a = 0 - \frac{7 a_{0}}{8} = \frac{a_{0}}{8}$
$t_{7 / 8} = \frac{1}{k} I n \frac{a_{0}}{a_{0} / 8} = \frac{I n 8}{k}$
$t_{7 / 8} = 3 (\frac{I n 2}{k}) = 3 t_{1 / 2}$
$n = 3$

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