Question

For a first order reaction, the plot of against log C gives a straight line with a slope equal to:

• A. $\left(\frac{k}{2}.303\right)$
• B. $\left(\frac{-k}{2}.303\right)$
• C. $\left(ln\frac{k}{2}.303\right)$
• D. $-k$

Answer 1

The correct option is B $\left(\frac{-k}{2}.303\right)$

$K=\frac{2.303}{t}log\frac{C_0}{C}\Rightarrow \frac{Kt}{2.303}=log{C}_0-logClogC=log{C}_0-\frac{Kt}{2.303}$