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Standard XII

Chemistry

Rate of Reaction

For a first-o...

Question

For a first-order reaction, the plot of t against log[a-x] gives a straight line with slope equal to:

\frac{2.303}{k}

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\frac{k}{2.303}

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\frac{- k}{2.303}

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2.303 k

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Solution

The correct option is B $\frac{- k}{2.303}$
$log \frac{a}{a - x} = \frac{k t}{2.303}$

$log (a - x) = \frac{- k t}{2.303} + log a$

$y = m x + c$

The plot of t against log[a-x] gives a straight line with slope equal to $- \frac{k}{2.303}$ .

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For a first-order reaction, the plot of t against log[a-x] gives a straight line with slope equal to:

The correct option is B −k2.303logaa−x=kt2.303log(a−x)=−kt2.303+logay=mx+cThe plot of t against log[a-x] gives a straight line with slope equal to −k2.303.

The correct option is B $\frac{- k}{2.303}$
$log \frac{a}{a - x} = \frac{k t}{2.303}$

$log (a - x) = \frac{- k t}{2.303} + log a$

$y = m x + c$

The plot of t against log[a-x] gives a straight line with slope equal to $- \frac{k}{2.303}$ .