Question

For a first order reaction, the plot of ‘t’ against log C gives a straight line with slope equal to:

• A. $\frac{K}{2.303}$
• B. $\frac{-K}{2.303}$
• C. $\frac{lnK}{2.303}$
• D. $-K$

Answer 1

The correct option is B $\frac{-K}{2.303}$

Since $K=\frac{2.303}{t}log\frac{a}{a-x}$
$log(a-x)=loga-\frac{kt}{2.303}$
Then slope is $\frac{-K}{2.303}$