For a first order reaction, the rate constant is $0.1 {s e c}^{- 1}$ . How much time will it take to reduce the concentration from initial value of $0.6$ $m o l^{- 1}$ to $0.06$ $m o l$ ${l i t}^{- 1}$ ?

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Solution

$K = 0.1 {s e c}^{- 1}$
$t = ?$
$t = \frac{2.303}{0.1} l o g (\frac{0.6}{0.06})$
$t = 23.03 s e c$

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For a first order reaction, the rate constant is 0.1 sec−1. How much time will it take to reduce the concentration from initial value of 0.6 mol−1 to 0.06 mol lit−1?

K=0.1sec−1t=?t=2.3030.1log(0.60.06)t=23.03sec

For a first order reaction, the rate constant is $0.1 {s e c}^{- 1}$ . How much time will it take to reduce the concentration from initial value of $0.6$ $m o l^{- 1}$ to $0.06$ $m o l$ ${l i t}^{- 1}$ ?

$K = 0.1 {s e c}^{- 1}$
$t = ?$
$t = \frac{2.303}{0.1} l o g (\frac{0.6}{0.06})$
$t = 23.03 s e c$