For a frequency distribution $8^{t h}$ decile is computed by the formula

D_{8} = l_{i} + \frac{\frac{N}{8} - C}{f} \times (l_{2} - l_{1})

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l_{1} + \frac{\frac{8 N}{10} - C}{f} \times (l_{2} - l_{1})

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D_{8} = l_{1} + \frac{\frac{N}{10} - C}{f} \times (l_{2} - l_{1})

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l_{1} + \frac{\frac{10 N}{8} - C}{f} (l_{2} - l_{1})

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Solution

The correct option is B $l_{1} + \frac{\frac{8 N}{10} - C}{f} \times (l_{2} - l_{1})$
A decile is any of the nine values that divide the sorted data into ten equal parts, so that each part represents 1/10 of the sample or population.
For a continuous distribution, the formula for $r^{t h}$ decile is given by $D_{r} = l_{1} + \frac{\frac{r N}{10} - C}{f} \times (l_{2} - l_{1})$
Substituting r = 8, we have $D_{8} = l_{1} + \frac{\frac{8 N}{10} - C}{f} \times (l_{2} - l_{1})$

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