For a function f:A→B, let the number of elements in set A and B be 4 and 5 respectively. If the number of many one functions are N, then value of N101 is
A
5.0
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B
5
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C
5.00
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Solution
Here, we have n(A)=4 and n(B)=5.
Clearly n(A)<n(B)
So, the total number of functions =5×5×5×5 =54=625
The total number of one-one functions =5×4×3×2=120 ∴ Number of many one functions = total number of functions - number of one one functions =625−120=505
So, N101=5