For a function f(x), a table is given below
The value of 5∫0f(x)dx by Trapezoidal’s rule is _____.
5∫0f(x)dx=h2[(y0+y5)+2(y1+y2+y3+y4)]
=12[(2+0.077)+2(1+0.4+0.2+0.1176)]
≃2.75