For a function, f(x) satisfying the following conditions 1)f(0)=6,f(2)=16 2)f has a minimum value at x=−4 3) For all x, f′(x)=∣∣
∣∣2ax4ax−13ax−b+3b2b+12ax+12b−2ax4b−4ax+3b+ax∣∣
∣∣,
the values of a and b are
A
a=12
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B
b=4
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C
a=13
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D
b=2
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Solution
The correct options are Aa=12 Bb=4 f′(x)=∣∣
∣∣2ax4ax−13ax−b+3b2b+12ax+12b−2ax4b−4ax+3b+ax∣∣
∣∣