For a function y-sin x-x- y- -1- 1-

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Integration by Substitution

For a functio...

Question

For a function $y = sin x,$
$x \in R, y \in [- 1, 1] .$

False

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x

[- 2 π, 2 π]

y = \sqrt{\frac{1 + sin x}{1 - sin x}} - s e c x

y = - \sqrt{\frac{1 + sin x}{1 - sin x}} + s e c x

[y + [y]] = 2 cos x

y = \frac{1}{3} [s i n x + [s i n x + [s i n x]]]

y = t a n^{- 1} (\frac{\sqrt{1 + sin x} - \sqrt{1 - sin x}}{\sqrt{1 + sin x} + \sqrt{1 - sin x}})

0 < x < \frac{π}{2}

\frac{d y}{d x}

cos

[sin x + [sin x + [sin x]]]

[y + [y]] = 2 cos x

y = \frac{1}{3} [sin x + [sin x + [sin x]]]

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