Question

For a gas $C_v=4.96cal/molK,$ the increase in internal energy of $2$ mole gas in heating from $340K$ to $342K$ will be :

• A. 27.80 cal
• B. 19.84 cal
• C. 13.90 cal
• D. 9.92 cal

Answer 1

The correct option is B 19.84 cal

Given,

$C_v=4.96cal/molK$

$n=2$

$\Delta T=342K-340K=2K$

Increase in internal energy,

$dU=n{C}_v\Delta T$

$dU=2\times 4.96\times 2=19.84cal$

The correct option is B.