For a gas having molar mass M, specific heat at constant pressure can be given as:

\frac{γ R}{M (γ - 1)}

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\frac{γ}{R M}

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\frac{M}{R (γ - 1)}

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\frac{γ R M}{γ + 1}

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Solution

The correct option is A $\frac{γ R}{M (γ - 1)}$

$C_{p} - C_{v} = R$
$∴ C_{p} - C_{v} = \frac{R}{M}$
Also, $\frac{C_{p}}{C_{v}} = γ$
\therefore \quad { C }_{ p }-\frac { { C }_{ p } }{ \gamma } =\frac { R }{ M } $
$∴ C_{p} = \frac{R . γ}{M (γ - 1)}$

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