For a gas molecular weight M specific het capacity at constant pressure is : $(γ = \frac{C_{p}}{C_{V}})$

\frac{R}{γ - 1}

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\frac{γ R}{γ - 1}

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\frac{γ R}{M (γ - 1)}

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\frac{γ R M}{(γ - 1)}

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Solution

The correct option is D $\frac{γ R}{M (γ - 1)}$
$C_{p} - C_{v} = R 1 - \frac{C_{v}}{C_{p}} = \frac{R}{C_{p}} 1 - \frac{1}{γ} = \frac{R}{C_{p}} \frac{γ - 1}{γ} = \frac{R}{C_{p}} C_{p} = \frac{r R}{γ - 1} C_{p} \times M = \frac{γ R M}{γ - 1}$
Heat capacity at constant pressure $= \frac{γ R M}{γ - 1}$

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