For a gaseous reaction 2B- A- Determine the relationship between equilibrium constant Kp and Kc-

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Relation between Kp and Kc

For a gaseous...

Question

For a gaseous reaction $2 B \to A$ , Determine the relationship between equilibrium constant $K_{p}$ and $K_{c}$ .

K_{p}

K_{c}

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K_{p}

K_{c}

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K_{p}

K_{c}

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None of these

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Solution

The correct option is B $K_{p}$ < $K_{c}$ .
For a gaseous reaction $2 B \to A$ , the equilibrium constant $K_{p}$ is less than $K_{c}$
$K_{p} = K_{c} (R T)^{Δ n}$
$Δ n = 1 - 2 = - 1$
$K_{p} = K_{c} (R T)^{- 1}$
$K_{P} < K_{c}$

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For a gaseous reaction 2B→A, Determine the relationship between equilibrium constant Kp and Kc.

The correct option is B Kp < Kc.For a gaseous reaction 2B→A, the equilibrium constant Kp is less than KcKp=Kc(RT)ΔnΔn=1−2=−1Kp=Kc(RT)−1KP<Kc

For a gaseous reaction $2 B \to A$ , Determine the relationship between equilibrium constant $K_{p}$ and $K_{c}$ .

The correct option is B $K_{p}$ < $K_{c}$ .
For a gaseous reaction $2 B \to A$ , the equilibrium constant $K_{p}$ is less than $K_{c}$
$K_{p} = K_{c} (R T)^{Δ n}$
$Δ n = 1 - 2 = - 1$
$K_{p} = K_{c} (R T)^{- 1}$
$K_{P} < K_{c}$