For a gaseous reaction, the following data were recorded:
Concentration in $m o l$ $L^{- 1}$ $0.1$ $0.05$ $0.025$ $0.0125$
Half life in $s e c$ $30$ $29.9$ $30.1$ $30$
The order of reaction is:

2

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1

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0

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Fractional

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Solution

The correct option is B $1$
For this order reaction
$t_{1 / 2} = \frac{ln (2)}{k} = \frac{0.693}{k}$
We find $t_{1 / 2}$ is invariant in given data so, order must be $1.$

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Similar questions

⟹ A + B \to

\begin{matrix} [A_{0}] & [B_{0}] & R a t e [R_{0}] M o l l i t r e^{- 1} & m o l l i t r e^{- 1} & m o l l i t r e^{- 1} s e c^{- 1} 0.1 & 0.2 & 0.05 0.2 & 0.2 & 0.10 0.1 & 0.1 & 0.05 \end{matrix}

A + B ⟶

A \to

[A] = 0.2

L^{- 1}

1.0 \times 10^{- 2}

L^{- 1}

m i n^{- 1}

\begin{matrix} p (k P a) & 26.6 & 40 & 53.3 t (m i n) & 150 & 99.8 & 75.3 \end{matrix}

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Concentration in $m o l$ $L^{- 1}$	$0.1$	$0.05$	$0.025$	$0.0125$
Half life in $s e c$	$30$	$29.9$	$30.1$	$30$