Question

For a given circuit, charge on capacitor $C_1$ and $C_2$ in steady state will be equal to

• A. $C_1(V_A-V_C),C_2(V_C-V_B)$ respectively
• B. $C_1(V_A-V_B),C_2(V_A-V_B)$ respectively
• C. $(C_1+C_2)(V_A-V_B)$ on each capacitor
• D. $\left(\frac{C_1{C}_2}{C_1+C_2}\right)(V_A-V_B)$ on each capacitor

Answer 1

The correct option is A $C_1(V_A-V_C),C_2(V_C-V_B)$ respectively

No current through the resistance.
Potential across capacitor $C_1$ is $(V_A-V_C)$
Hence charge on capacitor $C_1$ is $Q_1=C_1(V_A-V_C)$
Potential across capacitor $C_2$ is $(V_C-V_B)$
Hence charge on capacitor $C_2$ is$Q_2=C_2(V_C-V_B)$