For a given data rate the bandwidth βp of a BPSK signal and the bandwidth βo of the OOK signal are related as
A
βp=2β0/4
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B
βp=β0
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C
βp=β04
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D
βp=2β0.
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Solution
The correct option is Bβp=β0 BPSK transmits one bit per symbol, and the symbol rate is 1T, BPSK can transmit 1T bits per second which is same as OOK signal, so βp=β0