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Relation between Kp and Kc

For a given e...

Question

For a given exothermic reaction, $K_{p}$ and $K_{p}^{'}$ are the equilibrium constants at temperatures $T_{1}$ and $T_{2}$ respectively. Assuming that heat of reaction is constant in temperatures range between $T_{1}$ and $T_{2}$ . It is readily observation that :
(Given, $T_{2} > T_{1}$ )

A

K_{P} > K_{P}^{'}

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B

K_{P} < K_{P}^{'}

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C

K_{P} = K_{P}^{'}

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D

K_{=} \frac{1}{K_{P}^{'}}

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Solution

The correct option is A $K_{P} > K_{P}^{'}$
$log \frac{K_{2}}{K_{1}} = \frac{Δ H^{0}}{2.303 R} (\frac{1}{T_{1}} - \frac{1}{T_{2}})$
$T_{2} > T_{1}$ so $K_{p} < K_{p}^{'}$ (exothermic reaction)
(Given, $T_{2} > T_{1}$ )
$log \frac{K_{2}}{K_{1}} = \frac{Δ H^{0}}{2.303 R} (\frac{1}{T_{1}} - \frac{1}{T_{2}})$

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