Le Chatelier's Principle for Del N Greater Than Zero
For a given e...
Question
For a given exothermic reaction, KP and K′P are the equilibrium constants at temperatures T1 and T2 respectively. Assuming that heat of reaction is constant in temperatures range between T1 and T2, it is readily observation that:
A
KP>K′P
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B
KP<K′P
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C
KP=KP
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D
KP=1K′P
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Solution
The correct option is DKP>K′P For a given exothermic reaction, KP and K′P are the equilibrium constants at temperatures T1 and T2 respectively. Assuming that heat of reaction is constant in temperatures range between T1 and T2, it is readily observation that KP>K′P.
logK2K1=ΔHo2.303R(1T1−1T2)
T2>T1 So, KP>K′P (exothermic reaction)
(assuming T2>T1, although it is not mentioned, which temperature is higher. If T1>T2 then KP<K′P then answer should be (2)).
Thus for an exothermic reaction, when the temperature is increased, the equilibrium will shift in the reverse direction and the value of the equilibrium constant will decrease. This is in accordance with Le-Chatalier principle.