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Hydroboration Oxidation

For a given e...

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For a given exothermic reaction, K1 and K2, are equilibrium constants at temperatures T1, and T2 respectively. Assuming that heat of reaction is constant in temperature range between T1, and T2 it is readily observed that 1 K1>K2 2 K2>K1 3 K1 =K2 4 K1=1/K2

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K_{1}

K_{2}

are the equilibrium constants at temperature

T_{1}

T_{2}

T_{2} > T_{1}

Q. Assertion :Th equilibrium constant of the exothermic reaction at high temperature decreases. Reason: Since

ln \frac{K_{2}}{K_{1}} = \frac{{Δ H}^{o}}{R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]

and for exothermic reaction,

{Δ H}^{o} = - v e

\frac{K_{2}}{K_{1}} < 1

Q. For a given exothermic reaction,

K_{p}

K_{p}^{'}

are the equilibrium constants at temperatures

T_{1}

T_{2}

respectively. Assuming that heat of reaction is constant in temperatures range between

T_{1}

T_{2}

. It is readily observation that :
(Given,

T_{2} > T_{1}

)

Q. For a given exothermic reaction

K_{P}

K_{P}^{'}

are the equilibrium constants at temperatures

T_{1}

T_{2}

respectively. Assuming that heat of reaction is constant in temperature range between

T_{1}

T_{2}

is readily observed that__________.

Q. For a given exothermic reaction

K_{P}

K_{P}^{'}

are the equilibrium constants at temperatures

T_{1}

T_{2}

respectively. Assuming that het of reaction is constant in temperature range between

T_{1}

T_{2}

it is readily observed that.

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Hydroboration Oxidation

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