For a given gas $T_{c}$ = 40K hence, $T_{i}$ is:

40 K

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270 K

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135 K

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540 K

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Solution

The correct option is B 270 K
Inversion temperature in the Joule-Thomson effect at which the gas is neither cooled nor heated when allowed to expand without expending energy.
$T_{i n} = \frac{27}{4} T_{c}$
Inversion Temperature $(T_{i n}) = \frac{27}{4} \times 40 = 270 K$
Ans :- Option B.

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For a given gas Tc = 40K hence, Ti is:

The correct option is B 270 KInversion temperature in the Joule-Thomson effect at which the gas is neither cooled nor heated when allowed to expand without expending energy.Tin=274TcInversion Temperature (Tin)=274×40=270KAns :- Option B.

For a given gas $T_{c}$ = 40K hence, $T_{i}$ is:

The correct option is B 270 K
Inversion temperature in the Joule-Thomson effect at which the gas is neither cooled nor heated when allowed to expand without expending energy.
$T_{i n} = \frac{27}{4} T_{c}$
Inversion Temperature $(T_{i n}) = \frac{27}{4} \times 40 = 270 K$
Ans :- Option B.