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Atomic Number and Mass Number

For a given h...

Question

For a given hypothetical elementary parallel reaction,

दी गयी काल्पनिक प्राथमिक समान्तर अभिक्रिया के लिए,

where k₁ : k₂ = 1 : 1

जहाँ k₁ : k₂ = 1 : 1

Initially only 2 moles of A are present then the total number of moles of A, B and C at the end of 75% completion of the reaction is

प्रारम्भ में केवल 2 मोल A उपस्थित है, तो अभिक्रिया की 75% पूर्णता के अन्त में A, B तथा C के मोलों की कुल संख्या है

A

1

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B

5

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C

2

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D

3.5

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Solution

The correct option is D 3.5
Solution

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Similar questions

Q. For given hypothetical elementary parallel reaction, where

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Q. For non-negative real numbers

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Q. For the reaction

2 N O (g) + 2 H_{2} (g) \to N_{2} (g) + 2 H_{2} O (g)

The rate expression can be written in the following ways

\frac{d [N_{2}]}{d t} = k_{1} [N O] [H_{2}] \frac{d [H_{2} O]}{d t} = k [N O] [H_{2}] - \frac{d [N O]}{d t} = k_{1}^{'} [N O] [H_{2}] - \frac{d [H_{2}]}{d t} = k_{1}^{''} [N O] [H_{2}]

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Q. For the reaction

2 N O (g) + 2 H_{2} (g) \to N_{2} (g) + 2 H_{2} O (g)

The rate expression can be written in the following ways

\frac{d [N_{2}]}{d t} = k_{1} [N O] [H_{2}] \frac{d [H_{2} O]}{d t} = k [N O] [H_{2}] - \frac{d [N O]}{d t} = k_{1}^{'} [N O] [H_{2}] - \frac{d [H_{2}]}{d t} = k_{1}^{''} [N O] [H_{2}]

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