For a given liquid at a given temperature vapour pressure is given by- log10P mm - -400K-T-10Vapour pressure of the liquid at 400 K is-

The correct option is B 10^9 mm Vapour pressure of liquid a 400 K is given by #160; log_10P(mm)= 400(K)T+10 = 400400+10 =9 P=10 ...

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Standard XII

Chemistry

Boyle's Law

For a given l...

Question

For a given liquid at a given temperature vapour pressure is given by:

$l o g_{10} P (m m) = - \frac{400 (K)}{T} + 10$

Vapour pressure of the liquid at $400 K$ is:

9 m m

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- 9 m m

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10^{9} m m

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1^{- 9} m m

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Solution

The correct option is B $10^{9} m m$
Vapour pressure of liquid a $400$ K is given by

$l o g_{10} P (m m) = - \frac{400 (K)}{T} + 10$

$= - \frac{400}{400} + 10$

$= 9$

$P = 10^{9} m m$

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For a given liquid at a given temperature vapour pressure is given by:log10P(mm)=−400(K)T+10Vapour pressure of the liquid at 400K is:

The correct option is B 109mmVapour pressure of liquid a 400 K is given by log10P(mm)=−400(K)T+10=−400400+10=9P=109mm

For a given liquid at a given temperature vapour pressure is given by:

$l o g_{10} P (m m) = - \frac{400 (K)}{T} + 10$

Vapour pressure of the liquid at $400 K$ is:

The correct option is B $10^{9} m m$
Vapour pressure of liquid a $400$ K is given by

$l o g_{10} P (m m) = - \frac{400 (K)}{T} + 10$

$= - \frac{400}{400} + 10$

$= 9$

$P = 10^{9} m m$