For a given matrix A=⎡⎢⎣2−23−2−16120⎤⎥⎦, one of the eigen values is 3. The other two eigen values are.
A
2,−5
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B
3,−5
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C
2,5
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D
3,5
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Solution
The correct option is B3,−5 A=⎡⎢⎣2−23−2−16120⎤⎥⎦,
Trick: Let other eigen values are λ1,λ2,
Now, 3+λ1+λ2=2+(−1)+0=1 λ1+λ2=−2 .... (1)
Check options, only (b) satisfies (1)
Hence eigen values are 3,−5