1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Arrhenius Equation
For a given r...
Question
For a given reaction at temperature
T
, the velocity constant
k
, is expressed as:
k
=
A
e
−
27000
k
′
/
T
(
k
′
=
Boltzmann constant)
Given,
R
=
2
c
a
l
K
−
1
m
o
l
−
1
. Calculate the value of energy of activation.
Open in App
Solution
E
=
18
×
10
−
20
c
a
l
Suggest Corrections
0
Similar questions
Q.
The rate of a first order reaction gets doubled when the temperature is doubled from
T
1
t
o
2
T
1
(in K).
E
a
is nearly constant activation energy at 1386 kcal. What is the value of
T
1
?
(given R=2
c
a
l
K
−
1
m
o
l
−
1
,ln2=0.693)
Q.
The rate constant for decomposition of
C
O
C
l
2
(
g
)
according to following reaction
C
O
C
l
2
(
g
)
→
C
O
(
g
)
+
C
l
2
(
g
)
;
Δ
H
=
19
k
c
a
l
/
m
o
l
, expressed as
l
n
k
=
15
−
5000
T
Calculate activation energy for given reaction.
(
i
n
K
c
a
l
/
m
o
l
)
.
Q.
The activation energy for forward and backward reactions are
50
k
J
/
m
o
l
and
40
k
J
/
m
o
l
respectively. If
K
1
and
K
2
are the equilibrium constants of reaction at temperature
T
1
and
T
2
respectively and
T
2
>
T
1
then:
Q.
For a reaction, the rate constant is expressed as
k
=
A
e
−
40000
/
T
. The energy of the activation is:
Q.
Rate constant
k
of a reaction varies with temperature according to the equation
log
k
=
c
o
n
s
t
a
n
t
−
E
a
2.303
R
×
1
T
where
E
a
is the energy of activation for the reaction. When a graph is plotted for
log
k
vs
1
T
a straight line with a slope
−
6670
k
is obtained. The activation energy for this reaction will be:
(
R
=
8.314
J
K
−
1
m
o
l
−
1
)
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Arrhenius Equation
CHEMISTRY
Watch in App
Explore more
Arrhenius Equation
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app