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Types of Catalysis

For a given r...

Question

For a given reaction, energy of activation for forward reaction $(E_{a f})$ is $80 k J . m o l^{- 1} .$ $Δ H = - 40 k J . m o l^{- 1}$ for the reaction. A catalyst lowers $E_{a f}$ to $20 k J . m o l^{- 1} .$ The ratio of energy of activation for reverse reaction before and after addition of catalyst is :

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0.5

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1.2

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Solution

The correct option is D 2
$Δ$ H = E $_{f}$ E $_{b}$ -40 = 80 - E $_{b}$ E $_{b}$ = 120 kJ/mole,
catalyst lower the E $_{f}$ To 20 kJ/ mole for forward Rxn then E $_{f}$ ' = 20 kJ/mol
we know catalyst decreases the Activation energy equal amount
in both direction
E $_{b}^{'} = (12060)$ $= 60 k J / m o l$
$\frac{E_{b}}{E_{b}^{'}} = \frac{120}{60}$ =2.0

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