Question

For a given reaction, pressure of catalyst reduces the energy of activation by 2 kcal at ${27}^{0}C$. The rate of reaction will be increased by:

• A. 20 times
• B. 14 times
• C. 28 times
• D. 2 times

Answer 1

Answer: (C)

28 times

$\frac{k_2}{k_1}$ = $e^{\frac{E_{a\left(2\right)}-E_{a\left(1\right)}}{RT}}$

$k_2=28\times k_1$

So The Rate of reaction will be increased by 28 times