Question

# For a given wave , maximum particle velocity is 5 times the wave velocity corresponding to the equation, y=Asin(5t−0.05x) in which A , x are in metres and t is in seconds. The value of A is

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Solution

## We know that , Maximum particle velocity (vp)=ωA and wave velocity v=ωk Given , Equation of wave , y=Asin(5t−0.05x) Comparing this with, y=Asin(ωt−kx) we get, ω=5 rad/s and k=0.05 m−1 From the data given in the question , ωA=5×ωk ⇒A=5k=50.05=100 m

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