Question

For a glass of refractive index 1.732, the angle of incidence of ordinary light, for which the reflected beam is completely polarized is

• A. 75 degrees
• B. 30 degrees
• C. 60 degrees
• D. 5 degrees

Answer 1

The correct option is C 60 degrees

For the light beam to be completely polarized, according to Brewster's law.
Angle of incidence (i) = $ta{n}^{-1}\left(\mu \right)$
= $ta{n}^{-1}$ (1.732)
= ${60}^o$