For a hypothetical $H$ like atom which follows Bohr's model, some spectral lines were observed as shown. If it is known that line $^{'} E^{'}$ belongs to the visible region, then the lines possible belonging to ultra violet region will be: ( $n_{1}$ is not necessarily ground state). [Assume for this atom, no spectral series shows overlap with other series in the emmission spectrum]

B

and

D

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D

only

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C

only

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A

only

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Solution

The correct option is D $A$ only
In the given figure if line 'E' is in visible region then line belonging to ultraviolet region will have more energy than 'E' i.e. line A.

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\frac{3}{4} \times

H

9 t h

\begin{matrix} List - I & List - II (A) n = 6 \to n = 3 (In H- atoms) & (p) 10 lines in the spectrum (B) n = 7 \to n = 3 (In H atoms) & (q) Spectral lines in visible region (C) n = 5 \to n = 2 (In H-atoms) & (r) 6 lines in the spectrum (D) n = 5 \to n = 1 (In H-atoms) & (s) Spectral lines in infrared region (t) Spectral lines in U.V. region \end{matrix}

n_{2} = 5

n_{1} = 1

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