For a junction diode the ratio of forward current (If) and reserve current (Ir) is [e= electronic charges, V= voltage applied across junction, K= Boltzmann constant, T= temperature in Kelvin]
A
e−V/KT
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B
eV/KT
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C
(e−eV/KT+1)
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D
eeV/KT−1
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Solution
The correct option is DeeV/KT−1 Current in junction diode, I=I0(eeV/KT−1) In forward biasing, V is positive ; In reverse bias V is negative. Then Ir=I0 IFIr=I0(eeV/KT−1)I0=(eeV/KT−1)