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Question

For a junction diode the ratio of forward current (If) and reserve current (Ir) is
[e= electronic charges,
V= voltage applied across junction,
K= Boltzmann constant,
T= temperature in Kelvin]

A
eV/KT
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B
eV/KT
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C
(eeV/KT+1)
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D
eeV/KT1
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Solution

The correct option is D eeV/KT1
Current in junction diode, I=I0(eeV/KT1)
In forward biasing, V is positive ; In reverse bias V is negative. Then Ir=I0
IFIr=I0(eeV/KT1)I0=(eeV/KT1)

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