For a liquid, enthalpy of fusion is $1.435 k c a l {m o l}^{- 1}$ and molar entropy change is $5.26 c a l {m o l}^{- 1} K^{- 1}$ . The melting point of the liquid is:

0^{o} C

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{- 273}^{o} C

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173^{o} K

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100^{o} C

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Solution

The correct option is D $0^{o} C$
$Δ S_{f u s i o n} = \frac{Δ H_{f u s i o n}}{T_{m p}}$
$5.26 = \frac{1.435 \times 1000}{T_{m p}}$
$T_{m p} = \frac{1435}{5.26} = 273 K$

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