For a liquid- when heated in a vessel it is found that - a-67- r- The co-efficient of linear expansion of the vessel is -

The correct option is D γ _r21 γ_r=γ_a +γ_g #160; γ_r=γ_a +3α_g #160; #160; .....(1) γ_a=67γ_r Substituting for γ_a in (1), ...

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Byju's Answer

Standard X

Physics

Expansion In Liquids and Gases

For a liquid,...

Question

For a liquid, when heated in a vessel it is found that $γ_{a} = \frac{6}{7} γ_{r}$ . The co-efficient of linear expansion of the vessel is :

\frac{γ_{r}}{21}

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\frac{γ_{r}}{11}

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\frac{γ_{r}}{12}

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\frac{γ_{r}}{14}

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Solution

The correct option is D $\frac{γ_{r}}{21}$
$γ_{r} = γ_{a} + γ_{g}$
$γ_{r} = γ_{a} + 3 α_{g}$ .....(1)
$γ_{a} = \frac{6}{7} γ_{r}$
Substituting for $γ_{a}$ in (1),
$\frac{1}{7} γ_{r} = 3 α_{g}$
$∴ α_{g} = \frac{1}{3 * 7} γ_{r} = \frac{1}{21} γ_{r}$

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Similar questions

Q. For a liquid, the coefficients of apparent expansion '

γ_{a}

'and real expansion '

γ_{r}

' are related as:

LIST -I LIST -II

a) App. expansion e)Nature of vessel and liquid

b) Real expansion f) Nature of liquid

c) $γ_{a}$ g) Nature of Vessel&liquid and temperature

d) $γ_{r}$ h) Nature of liquid&temp.

The co-efficient of real expansion $γ_{r}$ of a liquid is 5 times the co-efficient of linear expansion of the material of the container in which the liquid is present. The ratio of the co-efficient of apparent expansion and real expansion of the liquid is:

The relation between the coefficient of real expansion ( $γ_{r}$ ) and coefficient of apparent expansion ( $γ_{a}$ ) of a liquid and the coefficient linear expansion ( $α_{g}$ ) of the material of the container is :

LIST -I LIST-II

a) $γ_{g}$ is +ve & < $γ_{r}$ e) liquid level does not

change

b) $γ_{g}$ is - ve f) liquid level increases

continuously

c) $γ_{g} = γ_{r}$ g) liquid level decreases.

d) $γ_{g} > γ_{r}$ h) liquid level first

decreases and then

increases.

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For a liquid, when heated in a vessel it is found that γa=67γr. The co-efficient of linear expansion of the vessel is :

The correct option is D γr21γr=γa+γgγr=γa+3αg .....(1)γa=67γrSubstituting for γa in (1), 17γr=3αg∴αg=13∗7γr=121γr

For a liquid, when heated in a vessel it is found that $γ_{a} = \frac{6}{7} γ_{r}$ . The co-efficient of linear expansion of the vessel is :

The correct option is D $\frac{γ_{r}}{21}$
$γ_{r} = γ_{a} + γ_{g}$
$γ_{r} = γ_{a} + 3 α_{g}$ .....(1)
$γ_{a} = \frac{6}{7} γ_{r}$
Substituting for $γ_{a}$ in (1),
$\frac{1}{7} γ_{r} = 3 α_{g}$
$∴ α_{g} = \frac{1}{3 * 7} γ_{r} = \frac{1}{21} γ_{r}$