For a man covering a certain distance at 6 km/hr and returning at 4 km/hr/ The average speed of the man is

102km.hr

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2.4 km/hr

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3.6 km/hr

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4.8km/hr

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Solution

The correct option is D 4.8km/hr
Given $u = 6 k m / h r, v = 4 k m / h r$
Average speed= $\frac{2 u v}{(u + v)} = \frac{2 \times 6 \times 4}{(6 + 4)} = \frac{48}{10}$
$= 4.8 k m / h r$

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