Question

For a material $Y={6.6\times 10}^{10}{N/m}^2$ and bulk modulus $K{11\times 10}^{10}{N/m}^2$, then its Poisson's ratio is:

• A. $0.8$
• B. $0.35$
• C. $0.7$
• D. $0.4$

Answer 1

The correct option is D $0.4$

Given that,

Young’s modulus $Y=6.6\times {10}^{10}N/m^2$

Bulk modulus $B=11\times {10}^{10}N/m^2$

We know that,

$Y=3K(1-2\mu )$

$6.6\times {10}^{10}=3\times 11\times {10}^{10}-66\times {10}^{10}\mu$

$-\mu =\frac{(6.6-33)\times {10}^{10}}{66\times {10}^{10}}$

$\mu =0.4$

Hence, the poisson’s ratio is $0.4$