Question

For a molecule with two like chiral carbon atoms, the number of optically active form is:

• A. 4
• B. 3
• C. 1
• D. 2

Answer 1

Answer: (D)

2

The number of racemic forms of molecules having $n$ different chiral carbons is $2^{n-1}$ whereas the number of configurational isomers of molecules having $n$ different chiral carbons is $2n$.

Therefore, For a molecule with two like chiral carbon atoms, the number of optically inactive form is $2$.