Question

For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume $T{V}^x=constant$ where $x$ is :

• A. $\frac{7}{5}$
• B. $\frac{2}{5}$
• C. $\frac{2}{3}$
• D. $\frac{1}{3}$

Answer 1

The correct option is C $\frac{2}{3}$

For an adiabatic process, $T{V}^{\gamma -1}$ = constant
Thus, $x=\gamma -1$
Now, for a monoatomic gas,
$\gamma =1.67$
Thus, $x=0.67$