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Question

For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume $$ TV^x =constant $$ where $$x$$ is :


A
75
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B
25
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C
23
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D
13
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Solution

The correct option is C $$ \dfrac{2}{3} $$
For an adiabatic process, $$ {T} {V}^{\gamma - 1} $$ = constant
Thus,  $$x = \gamma - 1 $$
Now, for a monoatomic gas,
$$ \gamma = 1.67 $$
Thus, $$x = 0.67$$

Physics

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