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Question

For a moving particle doing round trip which of the following options may be correct? Here , Vav is average velocity and uav the average speed.

A
|Vav|<uav
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B
|Vav|>uav
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C
Vav=0 but uav0
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D
Vav0 but uav=0
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Solution

The correct option is C Vav=0 but uav0
Average velocity is Net displacement/net time so in a round trip the displacement=0 so Vav=0 for round trip.
Average speed vav=net distance/time so vav can't be zero or vav0 provided there is some motion. so |Vav|vav
Option C is correct.

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