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Question

For a normal eye, the near point is 25 cm from the eye lens.The distance between eye lens and retina of the eye is 2.5 cm. What is the power of the eye lens?

A
4D
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B
40D
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C
36D
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D
44D
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Solution

The correct option is B 36D
u=25cm, V=2.5cm
Using 1f = 1u+ 1v= 125+ 12.5 = 925 cm1
P = 100f(incm)= 100 ×925 = 36D


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