For a nucleus to be stable, the correct relation between neutron number N and Proton number Z is

N > Z

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N = Z

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N < Z

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N \geq Z

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Solution

The correct option is D $N \geq Z$
For stability in case of lighter nuclei $\frac{N}{Z} = 1$ and for heavier nuclei $\frac{N}{Z} > 1$ .

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Similar questions

Q. In most stable nuclei, neutron number

N

and proton number

Z

has the relation

Q. Assertion :Light nuclei are most stable if

N = Z

, while heavy nuclei are more stable if

N > Z

. (

N \to

number of neutrons,

Z \to

number of protons). Reason: As the number of protons increases in a nucleus, the Coulomb's repulsive force increases, which tends to break the nucleus apart. So, to keep the nucleus stable, more number of neutrons are needed which are neutral in nature.

Q. In stable nuclei the number of protons

(Z)

and number of neutrons

(N)

M_{Z, N}, M_{Z, N - 1}

and the mass of the neutron,

Show that the minimum energy needed to separate a proton from a nucleus with Z protons and N neutrons is $△ E = (M_{z - 1, N} + M_{H} - M_{Z, n}) C^{2}$ Where $M_{Z, n}$ = mass of an atom with Z protons and N neutrons in the nucleus and $M_{H}$ = mass of a hydrogen atom. This energy is known as proton-separation energy.

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For a nucleus to be stable, the correct relation between neutron number N and Proton number Z is

The correct option is D N≥ZFor stability in case of lighter nuclei NZ=1 and for heavier nuclei NZ>1 .

The correct option is D $N \geq Z$
For stability in case of lighter nuclei $\frac{N}{Z} = 1$ and for heavier nuclei $\frac{N}{Z} > 1$ .