For a number to be divisibile by 6, it should also be divisible by 3 and 2 both respectively.

False

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True

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$18$ is divisible by both $2$ and $3$ . It is also divisible by $2 \times 3 = 6$ . Similarly, a number is divisible by both $4$ and $6$ . Can we say that the number must also be divisible by $4 \times 6 = 24$ $?$ If not give an example to justify the answer.

(i) All numbers divisible by 3 must also be divisible by 6

(ii) All numbers divisible by 6 must also be divisible by 3

18 is divisible by both 2 and 3. It is also divisible by 2 × 3 = 6. Similarly, a number is divisible by both 4 and 6. Can we say that the number must also be divisible by 4 × 6 = 24? If not, give an example to justify our answer:

Q. For a number to be divisible by 6, it has to be divisible by both ___.

Question 11

18 is divisible by both 2 and 3. It is also divisible by $2 \times 3 = 6.$ Similarly, a number is divisible by 4 and 6. Can we say that the number must be divisible by $4 \times 6 = 24 ?$ If not, give an example to justify your answer.

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