For a number to be divisible by 6, it has to be divisible by both ___.

2 and 4

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2 and 3

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3 and 4

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2 and 5

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Solution

The correct option is B 2 and 3
For a number to be divisible by 6, it has to be divisible by both 2 and 3.

Example:
18 is divisble by 2 as it is an even number.
18 is divisible by 3 as 1 + 8 = 9 and 9 is divisible by 3.
Therefore, 18 will be divisible by 6 as it is divisible by both 2 and 3.

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18 is divisible by both 2 and 3. It is also divisible by $2 \times 3 = 6.$ Similarly, a number is divisible by 4 and 6. Can we say that the number must be divisible by $4 \times 6 = 24 ?$ If not, give an example to justify your answer.

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For a number to be divisible by 6, it has to be divisible by both ___.

The correct option is B 2 and 3For a number to be divisible by 6, it has to be divisible by both 2 and 3. Example: 18 is divisble by 2 as it is an even number. 18 is divisible by 3 as 1 + 8 = 9 and 9 is divisible by 3. Therefore, 18 will be divisible by 6 as it is divisible by both 2 and 3.

The correct option is B 2 and 3
For a number to be divisible by 6, it has to be divisible by both 2 and 3.

Example:
18 is divisble by 2 as it is an even number.
18 is divisible by 3 as 1 + 8 = 9 and 9 is divisible by 3.
Therefore, 18 will be divisible by 6 as it is divisible by both 2 and 3.