For a pair of linear equations- a 1-12- b 1-2- c 1-6 and a 2-24- b 2-4- c 2-7 - Then the linear equation hasA- Two solutionsB- No solutionC- Four solutionsD- Infinite solutions

The correct option is B No solution When a_1/a_2= b_1/b_2 ≠ c_1/c_2, there exists no solution. Here, 12/24=2/4 ≠ 6/7 ⇒ 1/2= 1/2≠ 6/7 , Therefore,there ...

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Standard X

Mathematics

Tangent Secant Theorem

For a pair of...

Question

For a pair of linear equations, $a_{1}$ =12, $b_{1}$ = 2, $c_{1}$ = 6 and $a_{2}$ =24, $b_{2}$ =4, $c_{2}$ =7. Then the linear equation has

Four solutions

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Infinite solutions

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Two solutions

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No solution

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Solution

The correct option is D
No solution

When $\frac{a_{1}}{a_{2}}$ = $\frac{b_{1}}{b_{2}}$ ≠ $\frac{c_{1}}{c_{2}}$ , there exists no solution.

Here, $\frac{12}{24}$ = $\frac{2}{4}$ ≠ $\frac{6}{7}$

$\Rightarrow$ $\frac{1}{2}$ = $\frac{1}{2}$ ≠ $\frac{6}{7}$ ,

Therefore,there is no solution for the given linear equation.

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For a pair of linear equations, a1=12, b1= 2, c1= 6 and a2=24, b2=4, c2=7. Then the linear equation has

The correct option is D No solution When a1a2= b1b2 ≠ c1c2, there exists no solution. Here, 1224=24 ≠ 67 ⇒ 12= 12≠ 67 , Therefore,there is no solution for the given linear equation.

For a pair of linear equations, $a_{1}$ =12, $b_{1}$ = 2, $c_{1}$ = 6 and $a_{2}$ =24, $b_{2}$ =4, $c_{2}$ =7. Then the linear equation has