For a particle executing SHM. The kinetic energy 'K' is given by k = $k_{0} c o s^{2}$ wt. The maximum value of KE is.

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Solution

$K = K_{o} {cos}^{2} ω t$

${cos}^{2} θ \leq 1$

$⟹ {cos}^{2} ω t \leq 1$

$⟹ K E = k_{o} {cos}^{2} ω t \leq k_{o}$

Hence, $K E_{m a x} = k_{o}$

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For a particle executing SHM. The kinetic energy 'K' is given by k = k0cos2wt. The maximum value of KE is.

K=Kocos2ωtcos2θ≤1⟹cos2ωt≤1⟹KE=kocos2ωt≤koHence, KEmax=ko

For a particle executing SHM. The kinetic energy 'K' is given by k = $k_{0} c o s^{2}$ wt. The maximum value of KE is.

$K = K_{o} {cos}^{2} ω t$

${cos}^{2} θ \leq 1$

$⟹ {cos}^{2} ω t \leq 1$

$⟹ K E = k_{o} {cos}^{2} ω t \leq k_{o}$

Hence, $K E_{m a x} = k_{o}$